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0.25d^2=7
We move all terms to the left:
0.25d^2-(7)=0
a = 0.25; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·0.25·(-7)
Δ = 7
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{7}}{2*0.25}=\frac{0-\sqrt{7}}{0.5} =-\frac{\sqrt{}}{0.5} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{7}}{2*0.25}=\frac{0+\sqrt{7}}{0.5} =\frac{\sqrt{}}{0.5} $
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